An arithmetic series is a sequence which is being added.
For example, the sequence  2, 5, 8, ...  has a corresponding series  2 + 5 + 8 + ...

A series can be added, to give a sum. Here's a typical question:

Given the series 2 + 5 + 8 + ... , find the sum of the first 25 terms.

Notice that the series is arithmetic, because there is a common difference of 3.
In order to find the sum of 25 terms, or S25, we will need a formula.
Here it is:

Let's use this to find the sum S25 for the series 2 + 5 + 8 ..., where  a = 2,  d = 3, and  n = 25

Sn = n/2(2a + (n-1)d)
S25 = 25/2(2(2) + (25-1)(3))
S25 = 25/2(4 + (24)(3))
S25 = 12.5(4 + 72)
S25 = 12.5(76)
S25 = 950
So the sum of the first 25 terms in the series  2 + 5 + 8 ... is  950
.



Here's a different example.

Suppose a certain arithmetic series has first term 5 and last term 47. There are 15 terms in the series. Find the sum of all 15 terms.

Write the sequence: 5, ... 47 and there are 15 terms.

In this case we know  a = 5, and  n = 15. But we don't know  d.
We need a different formula. Here it is:

You can use this formula to find the sum of a series when you know the last term (tn).

a = 5    tn = 47    n = 15
Sn = n/2(a + tn)
S15 = 15/2(5 + 47)
S15 = 7.5(52)
S15 = 390
The sum of the series  5 + ... + 47, which has 15 terms, is 390.




Here's a final example, that's a little different.

Find the sum of the series  6 + 8 + 10 + ... + 44

Let's list what we know:  a = 6    d = 2     tn = 44
In order to find the sum of this series, we will have to find out how many terms there are first.

Step 1: Find  n, the number of terms
You already know how to do this, using the term formula, and letting tn be 44:
tn = a + (n - 1)d
44 = 6 + (n - 1)2
44 = 6 + 2n - 2
44 = 2n + 4
40 = 2n
20 = n

So the series has  20 terms.

Step 2: Find the sum.
Since we know the last term, we'll use the shorter formula:
Sn = n/2(a + tn)
S20 = 20/2(6 + 44)
S20 = 10(50)
S20 = 500

So the sum of the series  6 + 8 + 10 + ... + 44 is 500


Sequences & Series