![]() ![]() ![]() A torus has two radii. The first radius, the smaller one, is the radius of the cross-section r. The second radius R is the radius of revolution, which is the distance between the center axis and the center of the cross-section. Both of these measurements are needed to calculate the volume and surface area of a torus.
Let's try some examples: ![]() V = 2π2·R·r2 = 2π2(9)(42) = 2842.4 cm3 SA = 4π2·R·r = 4π2(9)(4) = 1421.2 cm2 Both calculations can be done in one step on your calculator. ![]() Find the inner radius r V = 2π2·R·r2 8000 = 2π2·(10)·r2 8000 ÷ (2π2·(10)) = r2 Enter in one step with brackets 40.53 = r2 6.4 cm = r ![]() Example 3: Inner radius = 3 cm Surface area = 10,000 cm2 Find R SA = 4π2·R·r 10000 = 4π2·R·3 10000 ÷ (4π2·3) = R Enter in one step with brackets 84.4 cm = R For Math 31 students (calculus): Here is the derivation of the Volume formula, by integrating Surface Area over r: Volume = ∫ (Surface area) dr V = ∫ (4π2·R·r) dr V = (4π2·R) · ∫ r dr V = (4π2·R) · r2/2 V = 2π2·R·r2 You can also differentiate the Volume formula with respect to r to get Surface Area: SA = d/dr (2π2·R·r2) SA = (2π2·R) d/dr r2 SA = ( 2π2·R) 2r1 SA = 4π2·R·r |